How to swap two numbers using XOR in C#:
XOR operator can be used to swap two numbers. This is a bitwise operation and it converts the number to binary and performs XOR on each digit of both numbers.
In C#, XOR is denoted by ^.
The below algorithm is used to swap two numbers using XOR:
first = first ^ second
second = first ^ second
first = first ^ secondWhere first and second are the first and second numbers.
We can write a C# program that will take both numbers as input from the user and swap them using XOR.
C# program:
Below is the complete C# program:
using System;
public class Program
{
public static void Main()
{
int first,second;
Console.WriteLine("Enter the first number : ");
first = int.Parse(Console.ReadLine());
Console.WriteLine("Enter the second character : ");
second = int.Parse(Console.ReadLine());
Console.WriteLine("Before swapping first = {0}, second = {1}",first,second);
first = first ^ second;
second = first ^ second;
first = first ^ second;
Console.WriteLine("After swapping first = {0}, second = {1}",first,second);
}
}Here,
- first and second are two integer variables to hold the user input values.
- It is reading these numbers as input from the user.
- It prints the numbers before and after swapping is done.
- For swapping, it uses XOR similar to the algorithm we discussed above.
Sample output:
If you run this program, it will give output as like below:
Enter the first number :
10
Enter the second character :
11
Before swapping first = 10, second = 11
After swapping first = 11, second = 10As you can see here, the entered numbers are swapped.
