This tutorial is to find *Harshad* or *Niven* number in Java. A *Harshad* or number or even number is a number that is divisible by its digits.

For example, *63* : The sum of its digits is_ *6+3 = 9*. 63_ is divisible by *9* . So it is a *Harshad* number. But *64* is not. Because *6+4 =10* and_ _64%10__ or reminder is not zero. We will write one Java program to find all Harshad numbers starting from 1 to 100.

All one digits numbers are Harshad number, because each number is divided by that number.

### Java program to find all Harshad/Niven numbers from 1 to 100 :

```
/*
* Copyright (C) 2017 codevscolor.com
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
/**
* Class to find Harshad / Niven number from 1 to 100
*/
public class Test {
static void print(String value) {
System.out.print(value);
}
/**
* find sum of digits of a number
*
* @param number : number to find the sum of its digit
* @return : sum of all digits
*/
static int findSumOfDigits(int number) {
int sum = 0;
while (number > 0) {
sum += number % 10;
number /= 10;
}
return sum;
}
public static void main(String[] args) {
for (int i = 1; i < 101; i++) {
if (i % findSumOfDigits(i) == 0) { //if sum of digits can divide the number, then it is a Harshad number
print(i + " ");
}
}
}
}
```

### Output :

`1 2 3 4 5 6 7 8 9 10 12 18 20 21 24 27 30 36 40 42 45 48 50 54 60 63 70 72 80 81 84 90 100 `

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