Python program to find the cube sum of first n numbers

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Python cube sum of first n numbers

Introduction :

This program will show you how to get the cube sum of first n natural numbers in python. The program will take the value of n as an input from the user, calculate the sum of cube and print it out.

We will solve this problem by using one loop and recursively.

 

Method 1: Using a loop :

Get the value of n, call one method to find the total cube sum and use one loop to find that out :

def findCubeSum(n):
    sum = 0
    for value in range(1, n+1):
        sum += value**3
    return sum


n = int(input("Enter the value of n : "))

print("Cube sum : ", findCubeSum(n))

 

Sample Output :

Enter the value of n : 5
Cube sum :  225

Enter the value of n : 10
Cube sum :  3025

Enter the value of n : 4
Cube sum :  100

Python cube sum loop

 

Method 2: Recursive approach :

We can also call the same method recursively to find out the cube sum :

def findCubeSum(n):
    if(n<=1):
        return 1;
    return n**3 + findCubeSum(n-1)


n = int(input("Enter the value of n : "))

print("Cube sum : ", findCubeSum(n))

Here, findCubeSum method is called recursively. It will print the same output as the above example.

Python cube sum recursive

Categories: python

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