C++ program to pass a structure to a function

Pass structures to a function in C++:

Structures are used to group different types of variables in C++. We can use structures to hold data and also we can pass any structure data to a function. In this tutorial, we will learn how to pass data in structures to a function in C++.

C++ program to pass data in structure as arguments to a function:

Let’s take a look at the below program:

#include <iostream>

using namespace std;

struct User
{
    string userName;
    int age;
};

void printUserInfo(User user)
{
    cout << "User name: " << user.userName << ", age: " << user.age << endl;
}

int main()
{
    User user;

    cout << "Enter the name of the user: " << endl;
    cin >> user.userName;

    cout << "Enter the age of the user: " << endl;
    cin >> user.age;

    printUserInfo(user);
}

Here,

User is a structure to hold one string for user name and one int to hold the age.
In the main method, we are creating one User object to hold the user data.
Using cout and cin, we are reading the user data and storing it in user.
The last line is passing the user data to printUserInfo and this function is printing the values in the user object.

It will give the below output:

Enter the name of the user: 
alex
Enter the age of the user: 
20
User name: alex, age: 20

Compilation error:

We need to declare the structure before the function always. Otherwise, it will throw a compilation error.

#include <iostream>

using namespace std;

void printUserInfo(User user)
{
    cout << "User name: " << user.userName << ", age: " << user.age << endl;
}

struct User
{
    string userName;
    int age;
};

int main()
{
    User user;

    cout << "Enter the name of the user: " << endl;
    cin >> user.userName;

    cout << "Enter the age of the user: " << endl;
    cin >> user.age;

    printUserInfo(user);
}

It will throw an error:

error: unknown type name 'User'

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