### C program to find remainder without using modulo operator :

In this tutorial, we will learn how to find the *remainder* without using *modulo operator (%)* in *C programming language*. The algorithm that we are going to use is as below :

### Algorithm :

- First read the
*number*and*divisor*as entered by the user. - Keep
*subtracting*the*divisor*from the*number*and set the value to the*number*till the*number*become*less*than*divisor*. - If the
*number*becomes less than*divisor*, it should be the required*remainder*. - Print out the result.

For example, if the number is *10* and divisor is *3*. First we will calculate *10 - 3* which is *7* and set this value to the *number*. Next time, it is *7 - 3* which is *4*. Next number will be *4 - 3 = 1*. Since *1* is less than *3*, it is the remainder. Let’s take a look into the program :

### C program :

```
#include
int main()
{
//1
int no,divisor,remainder;
//2
printf("Enter the number : ");
scanf("%d",&no);
//3
printf("Enter the divisor : ");
scanf("%d",&divisor);
//4
while(no >= divisor){
no = no - divisor;
}
//5
remainder = no;
//6
printf("The remainder is %d ",remainder);
return 0;
}
```

### Explanation :

*The commented numbers in the above program denotes the step number below :*

- Create three
*integer*variables to store the value of the number (*no*), divisor (*divisor*) and remainder (*remainder*). - Ask the user to enter the variable and store it in variable
*no*. - Ask the user to enter the divisor and store it in variable
*divisor*. - Run one
*while*loop. Check if*no*is greater than*divisor*and if yes, store the value of*no - divisor*in*no*. Do this till the value of*no*becomes less than*divisor*. - Assign the final value of
*no*to the variable*remainder*. - Finally, print out the value of
*remainder*.

### Sample Output :

```
Enter the number : 12
Enter the divisor : 4
The remainder is 0
Enter the number : 555
Enter the divisor : 4
The remainder is 3
```